MA5:=MA(C,5);MA10:=MA(C,10);三连阴:=COUNT(C< REF(C,1),3)=3;五连阳:=COUNT(C>REF(C,1) AND C>O,5)=5;XG:C>O AND C>REF(C,10) AND C>MA5 AND O< MA5 AND REF(L,1)>REF(MA10,1) AND REF(C,1)< REF(MA5,1) AND REF(三连阴,4)=1 AND C/REF(C,1)<=1.05;
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